Square Root of 244 Okay Again

(i) 12544

By using long division method

∴ the square root of 12544

√12544 = 112

(two) 97344

By using long sectionalization method

∴ the square root of 97344

√97344 = 312

(three) 286225

By using long partition method

∴ the square root of 286225

√286225 = 535

(4) 390625

By using long segmentation method

∴ the square root of 390625

√390625 = 625

(five) 363609

By using long division method

∴ the square root of 363609

√36369 = 603

(six) 974169

∴ the square root of 974169

√974169 = 987

(vii) 120409

By using long division method

∴ the square root of 120409

√120409 = 347

(8) 1471369

Past using long sectionalisation method

∴ the square root of 1471369

√1471369 = 1213

(ix) 291600

∴ the square root of 291600

√291600 = 540

(x) 9653449

By using long division method

∴ the foursquare root of 9653449 √9653449 = 3107

(xi) 1745041

By using long segmentation method

∴ the square root of 1745041

√1745041 = 1321

(xii) 4008004

By using long division method

∴ the foursquare root of 4008004

√4008004 = 2002

(thirteen) 20657025

By using long sectionalization method

∴ the foursquare root of 20657025

√20657025 = 4545

(14) 152547201

By using long division method

∴ the square root of 152547201

√152547201 = 12351

(fifteen) 20421361

By using long division method

∴ the foursquare root of 20421361

√20421361 = 4519

(xvi) 62504836

By using long sectionalization method

∴ the square root of 62504836

√62504836 = 7906

(xvii) 82264900

By using long division method

∴ the foursquare root of 82264900

√82264900 = 9070

(xviii) 3226694416

By using long sectionalization method

∴ the square root of 3226694416

√3226694416 = 56804

(xix) 6407522209

By using long division method

∴ the square root of 6407522209

√6407522209 = 80047

(xx) 3915380329

By using long division method

∴ the foursquare root of 3915380329

√3915380329 = 62573

Video transcript

[Music] hullo love student i am sunita and i from leader learning and i am here to help you detect the square root of all these numbers correct you lot take 20 numbers and each of them getting bigger than the previous right and then nosotros are going to accept some fun doing the foursquare root of each of these by the long sectionalization method so now what i am going to practice is i am going you right in front of y'all you see this table then i am going to be writing the answers of each of them right i will be writing the number here this will be the number and here will be your foursquare root which we volition detect all right at present each sum i will do over hither in this section and after each sum is done i volition rub it out and outset the next one merely before that i will write the answers hither okay okay and so the first one is one 2 five four four one two five 4 four right and then let me write that number here one two 5 four 4 and then past the division method y'all know when we use the sectionalisation method for finding the square root nosotros start by pairing the numbers from the extreme right in this mode so i'm and then i have ane i take to commencement with so one ones are one right and so i do the subtraction i get 0 25 i bring down the next pair of numbers i double my divisor right and i look for a number like i right 1 ones are one and one twos are two so i have 21 here i do the subtraction i have a remainder of iv i bring down the next pair of numbers and i double my divisors terminal digit that is one. so i get 22 now i look for a number like 2 is perfect 2 into 2 22 gives me 444 and my square root is i ane two right so i volition write that hither i volition write information technology in red all right and then ane 1 2 is my foursquare root of the first number right now the second number is now let me rub this out and let me put in my 2d number so the 2nd number is nine seven three four 4 so let me do that here nine seven three four iv again i start pairing the numbers from the extreme right so i have a 3 hither three 3s are 9 i do the subtraction 0 i bring down the side by side 2 digits 73 i double my divisor i get 6 and so when i multi i put a 1 here and almost the quotient and in the quotient section and when i multiply one past 61 i become 61 i practice the subtraction i get 12 i bring down the next ii numbers i double the final digit of my previous divisor that is one so i go 62 only the concluding digit i double correct now i put a 2 here so that 2 into 6 22 gives me 1 2 4 4. so for this final step i need to find that number whose square ends in the last digit of this terminal this the last pair that i bring down here all right then the last number has to be a square number square has to end in this digit and then 2 2s are 4 right ok so getting back to the sum i have done the subtraction residual is 0 then i plant the square root of the second number nine vii 3 four four to exist 3 1 ii all correct now i come up to the tertiary number is permit me write it down here information technology is two 8 6 ii 2 5 two eight vi 2 2 v okay so let's do that some now so let me erase this working for the next sum and so the number is ii 8 6 2 2 v. so again i grouping the numbers in pairs so i merely have to work with the 28 so five fives are 25 is the square which is less than 28 i do the subtraction i bring down the side by side pair of digits i double my divisor and a three would work hither fine because iii into 103 gives me 309 i do the subtraction i have 3 53 i bring down the 25 all right i double the last digit of my divisor i get i 0 six and i remember five should be fine right so how is it work 5 v's are 25 5 sixes are 13 to 32 at that place's a cypher there so 32 comes down fine and five ones are v and then my remainder is zero and i institute the foursquare root of the third number to be 5 3 5. [Music] at present comes the 4th number which is iii 9 0 half dozen 2 5. okay let'south outset working on that era is this permit me write down the number information technology is three 9 0 six 2 5 half-dozen ii 5 so again i beginning pairing the digits and i take it like this and then i accept to do work with 39 outset so 6 6 is a the square of vi is 36 which is less than 39 i get a remainder of three i bring down the next two digits i double my divisor and i have to put a two here because 2 into 122 is the merely number which volition be less than 306 and then that is 244 i exercise the subtraction i get 2 hither and a 6 here right and i bring down 25 i have 124 here and a five volition be but fine right so i 2 4 5 into 5 gives me 6 ii ii 5 and i take found my square root so the foursquare root of the given number is 625 correct we know that 625 is the square root of 2 is the foursquare of 25 merely the square of half dozen twenty five itself is 3 nine nix six 2 five ok now nosotros come to the fifth sum is three six iii half dozen 0 ix oops pitiful blackness it should be 3 half-dozen 3 6 0 9 all right so i'g going to erase this working hither and let'south write down the number three half dozen 3 half-dozen 0 9. then over again i offset pairing the numbers here so i have a 36 so half-dozen six is at 36 is just perfect i take a 0 remainder so i bring downwards the 36 i double my divisor i accept 12 merely a 0 will do here because any number will exist greater than 36 and so i practice the subtraction and i bring downwards the adjacent pair of numbers i bring downwardly my divisor as it is and a 3 will be fine right then three iii'due south are 9 0 3 are vi three ones are three and then my square root of three six three six naught nine is vi zero 3 we come to the 6th sum which is nines oops once again we need the black the black we need 9 vii four 1 6 ix all right so let'south erase this and allow me write down that number 9 7 4 1 half dozen 9 so let's start pairing the digits so i take to deal i have to work with 97 so i remember ix nines are 81 that'south the furthest i tin can go all right and so i do the subtraction and i get sixteen i bring downward 41 i double my divisor and what is that number which volition work in this case information technology is 8 all right so 188 into viii gives me one 5 zero four so i do the subtraction i have 7 and a 3 and a one all right so i bring down the 69 and i double the final digit of my divisor i go 96 and 1 and what number will i multiply this with 7 so 1967 into 7 7 7's are 49 seven sixes are 42 and 446. seven nines are 63 and 63 and 467 seven ones are seven and six thirteen. so that'southward a residue of 0 and i've got my square root of 974169 to be 987 correct now nosotros come up to the seventh sum which is 1 2 0 iv 0 9 one two 0 4 0 9 okay let's detect the foursquare root of that i'll erase this i hope you're agreement the working so let me write this number it is 1 2 0 iv 0 ix right so we kickoff pairing off and it it results in 12 being the beginning number so i go for 3 3s are 9 my remainder is 3 0 4 i double i double the divisor i accept 6 here so i think 4 will fit the bill four fours are 16 four sixes are 24 and 125 that's eight and that's 4 and i bring downward the last two digits 0 9 i as well double the last digit of my divisor i go 68 because i add iv to it iv to the previous at present what number will [Music] sit here well it volition exist seven seven sevens are 49 nine carry iv seven eights are 56 and 4 16 7 6 are 42 and six 40 eight so at that place i get my square root so the foursquare root of the number is three four seven at present i get to the 8th sum which is i four seven one three six nine okay permit me erase this and i'm going to fill in that number here ane 4 seven one iii half-dozen nine and so let's start pairing from the right and one on its own and then one ones are 1 i do the subtraction 0 47 i have a 2 so i'll have to satisfy myself with the 2 is fine yes then 2 into 22 gives me 44. i do the subtraction residual of iii i bring down 1 iii correct so i double this concluding digit i get 2 4 and 1 here and a one here 241 into 1 is 241 and exercise the subtraction i get 72 i bring down the 69 i double the last digit hither so i get 242 and a iii correct 3 will be fine here so i have three 3's are ix 3 ii's are 6 3 fours are twelve three twos are six and ane 7 perfect remainder of zero and so i found the foursquare root of this eighth number to be one two i three one 2 one three all right okay now let's get to the 9th number the ninth number reads two 9 one vi zero goose egg okay let'south practice the sum i accept a feeling this is going to be a short and sweet sum let'southward see so i have hither 2 9 1 6 0 0 then i pair the digits this way so the pairing is a fleck at a slant correct okay permit me redo it information technology looks a bit untidy that's two ix one 6 0 0 and then there i've paired them so i accept to work with 29 five fives are xx 5 residual of iv i bring downwards the sixteen i double my divisor and a iv will be just perfect four fours are sixteen four four and six oops is my sum over considering i accept a remainder of nada but these ii zeros are there right now for these two zeros all i have to practice is put ane 0 on top and my answer is 540 so let me put that hither the square root of the given number is 540. then it did work out to exist a short sum right okay so at present the tenth sum and we are halfway volition exist permit me write downwards the number it is 9 six five nine six v iii four four 9 three four four nine and so let me write down that number and then that is nine six five three four four nine so let'south offset pairing the digits so three is on nine is on its own correct so three threes are nine and i bring down the adjacent two digits is 65 i double my divisor and one will exist just fine 61 into 1 gives me 61. 4 is my rest i bring down the 34 i double this terminal digit i get 62 right and with 62 yes i can't put any number because even if i put a 1 information technology is going to be 621 which is more than 434 and then i will put a 0 0 into 620 gives me 0 i do the subtraction i get a remainder of 434 i bring downward the last 2 digits and i double the last digit which is a 0 so that's fine then i have to put a seven here correct and then seven sevens are 49 seven twos are 14 seven sixes are twoscore two and one 40 three so my foursquare root of the given number is 3 i 0 7 3 1 0 and 7 right okay now allow's motility to the 11th sum the numbers are slowly getting bigger but that'due south non a problem once we know the method nosotros can deal with whatever whatever number of numbers to discover the square root so let's write down the next number which is um the tenth number deplorable the eleventh number one seven 5 no i'm lamentable one 7 4 5 [Music] 0 four 1 is that right yes okay let me write that number here one seven oops ane 7 four five 0 4 ane and i'm going to pair them upwards so i have i 1 1 i exercise the subtraction 74 is my remainder i double this correct so i tin can put a 3 here 23 and i multiply 23 by 3 i go 69 correct okay now let me do the subtraction i get v i bring down the 50. i also double this final digit so i have 26 and here what would be what would piece of work is 2 considering 262 multiplied by 2 gives me two [Music] 524 and my remainder is 26 i bring down the 41 i double the last digit that is ii and then i get 264 and a 1 is just plenty ane into 2 6 four 1 is ii six four ane and i have found my foursquare root correct so the square root of the given number is one three two one all correct now comes the twelfth sum the twelfth sum says the number is four zero zero eight 0 0 4 okay and so allow me erase this sum and get-go with the new number that is 4 0 0 8 0 0 4. it'southward a strange looking number then let'south start pairing upwardly from the right and we become this so we we have a four there and so two twos are iv then a remainder of nada nosotros bring down the adjacent pair of zeros nosotros double the two we go four and this has to be zero nothing else considering nosotros have to go a 0 hither as well so there is nothing here we bring down 80 the next pair of numbers and i bring downwardly the 40 equally it is all correct now i have to add together a number here so that the production gives me less than 80 correct so this has to be 0 one time again because even if i put a 1 it becomes 401 so again fourscore is my remainder now i bring downwardly the 0 4 and my 400 is as it is so hither i put a ii and i put a two here and what do i go when i multiply 8004 so my square root is 2002 allow's go to the 13th sum all correct what is the number in the 13th sum it is 2 0 6 say 5 seven 0 ii v okay so let'south work on that two zero half dozen five seven goose egg 2 five okay allow's pair of the numbers from the extreme right and nosotros accept 20 to work on first so 4 fours are sixteen that's the square which is closest and less than 20 i bring down the side by side pair of numbers i double my divisor and i have 5 over here because 85 into 5 will give me 425 5 fives are 25 425 i have a remainder of forty i bring downward lxx i double the v and i become 90 right all correct so 19 now what works with 90 i remember 4 should be fine because 904 into 4 gives me 4 4s are 16 9 4s are 36 all right and the remainder is 554 right 554 is information technology [Music] simply a minute 4 six is one five sorry four fifty four knew something was incorrect there so let'southward rub out this 5 and make it a iv so that's 454 and um yes nosotros bring down the last 2 digits 25 i double this 908 i go and it has to be a five [Music] right that'due south an interesting number we've got on top four five four v five fives are 25 40 two and five nines are 45 and then this is a number four five 4 5 is the square root of the given number okay now let's become to the fourteenth sum the fourteenth sum whose square root we have to find is then the 14th number is 1 v 2 five four seven 2 0 one oh the numbers are getting actually long i promise they fit in my tabular array okay let's erase this one and let's start off with this huge number ane v 2 five four seven two goose egg one okay let me kickoff pairing them there we are to start with a one so 1 ones are 1 i bring down 52 i double this correct then what will this be um 2 should be fine right 22 into 2 gives me 44. and so i take viii as a residue i bring downwardly 54 i double my last digit and i become 24 and i will put three here this ane 3 threes are nine three fours are twelve three two are vi and 1 seven twenty ix i go one twenty five i bring down the side by side pair of digits digits which is lxx two and i double the last digit of 243 and i get 246 and v should do fine i call up so five fives are 25 five sixes are xxx and 232 5 v fours are twenty and iii twenty three 5 twos are ten into twelve i do the subtraction i accept seven four ii correct i bring down the last 2 digits i double the last digit of my divisors and i become 70 and 24 is as it is and this has to be one and naught else correct because 2 4 seven 0 i into 1 is two iv seven 0 1 and nosotros take constitute our square root so the square root of our number was or rather is one ii three five i all right okay now allow's go to the seventeenth sum the seventeenth sum no rather fifteenth sum for getting my roman numerals then the fifteenth sum says 2 zero 4 ii ane 3 6 i 2 one 3 half dozen 1 right now all these are perfect squares mind you okay and then let'southward erase that what yep and let me write it here ii 0 4 two ane three six one so that'south i two iii and four so four pairs of numbers we have to practice deal with the xx first so 4 fours are 16 that'southward 4 bring downward the rest for bring down the next pay 42 double my divisor which is viii right and here what volition i get i remember a 5 should be fine right then i'll put a five here and a 5 here and then 5 five'southward are 25 5 eight are xl into 42 so i have a seven and a one and i bring down my xiii i double the last digit i get ninety and i shall put just 1 because anything more than one will be too much and so i minus 901 from this and i'm left with 812 yes so i bring downward the adjacent pair of digits i double my last digit of the divisor i get 902 and this has to be nine correct 9 nines are 81 carry 8 nine twos are 18 and 8 twenty vi nine nines are eighty 1 then i institute my foursquare root of the fifteenth number to exist iv five 1 9 4 5 1 ix now let's go to the 16th sum which reads 625 6 2 5 0 4 0 4 8 iii six viii 3 6 alright and then allow me erase this sum all right at present the sum is 625 0 4 8 3 half-dozen then i start pairing them and i take to work with 62 okay then what is that perfect square which is less than 62 it is 49 so i volition start with the 49 vii sevens are 49 i practise the subtraction and i take 13 correct then i bring downwardly the next ii digits 50 i double my divisor xiv and i think ix will be fine here and then nine nines are 81. 9 fours are 36 and eight 44 ix ones are 9 and iv 13 a remainder of merely 9 right ok then i bring down 48 is that fine i double the nine here i get 18 and 158 and here of course i'll have to put a 0 because whatsoever even 1 will exist too much so i get a 0 hither i exercise the subtraction 948 and i bring down 36 my divisor remains every bit information technology is and i think a six will be fine because half-dozen sixes are 36 in that location is a 0 there half-dozen eight are 48 6 v'due south are 30 and 4 34 carry iii vi ones are vi and three nine so my foursquare root of this number was 7906 okay at present we come to the 17th sum whoops one minute yeah that'south the 17th sum which reads eight to 2 correct 8 two 2 vi 4 ix zero zero okay so allow'due south erase this and put the new number in place so that's 8 ii ii six 4 ix 0 0. so we start pairing from the right towards the left and we have 82 to work with offset so nine nines are 81 the subtraction we get 1 as a remainder we bring down 26 nosotros double ix and we get 18 it has to be a 0 any other numbers likewise big so i have a balance of 126 i bring downward 49 and 180 as it is and this has to exist seven right considering 7 see the magic 7 sevens are forty nine seven eighths are fifty six vii ones are 7 and five twelve perfect zippo and now we have two zeros here and so we'll put one zero to stand for those two so the foursquare root of the given number is 9 aught seven zero we come up to the nineteenth sum no it's eighteen sum so eighteenth sum says the number is 8 no iii 2 two six half-dozen nine four iv i six oh this table is getting small showtime for the numbers all right so let'south erase the sum we did before and nosotros'll put in the new number and then the number is iii 2 2 6 6 9 4 4 one half-dozen so allow's kickoff pairing lots of pairing to do here okay then nosotros accept to work with the 32 first correct so what is that perfect square information technology is 25 5 five's are 25 i do the subtraction i have seven here oops sorry about that 7 all right i bring down the 26 i double my five i get 10 and this will have to be six six sixes are 36 and six ones are half-dozen so i have 0 and 90. all right now i bring the adjacent ii digits 69 i double my last digit i go 112 and what number will work here it volition be 8. all right so ane 1 two eight into eight gives me 8 eighths are sixty four eight twos are sixteen and six is twenty 2 eight ones are eight is into ten eighteens are eight and one nine nine zero two four i practice the subtraction i get 45 as remainder i bring down the next two digits 44 i double the last digit of my device up and i go 36 and 1 i remains as it is now here i will have to be putting a 0 because any other number is too big so my residue remains as 4 5 iv 4 i bring down the last ii digits this remains as it is because the last digit is 0 and i call back a iv will be fine right [Music] yes then 4 4's are sixteen iv half-dozen'due south are 24 carry two four threes are twelve and two fourteen four ones are four and one 5 and a 4 i practise the subtraction i get nada and so the square root of that number is five half dozen eight nix four v six 8 aught four right so if someone asked you what is the square of five six viii zero four you take the answer with you right now the second last sum which is now i better start from this end six four nada seven five two 2 two 0 9 all correct and then let's erase what we did and put in the new sum and so the number is vi iv 6 4 0 7 v ii 0 nine okay let's pair the numbers 0 nine 22 52 0 vii and 64. then 64 is there means it has to be 88 64. right a residuum of 0 nosotros bring down the 0 vii we double this now the number has to be 0 so i have a remainder of 7 i bring down 52 i have 160 here again it has to exist 0 because any other number is too big right so i become 0 here my remainder is 752 i bring down the 22 and i accept 1600 here all right and i'll put a four correct so i take 4 fours are 16 zero 4 sixes are 24 four ones are 4 into six now i do the subtraction i have six zero two 1 in the final two digits zero nine i double the last digit here i have viii 0 0 16 and i think oh i forgot there is a 1 here likewise i am and then sad yeah and then now i take um 7 should be fine shall we cy okay vii sevens are 49 deport iv seven eights are 56 and four 16 seven zeros are zero seven sixes are twoscore two seven ones are seven and 4 eleven so that is why seven was just perfect so there we have a square root of the given number to be fourscore 047 allow me write that here eighty 047 and the final number of our sum is 3 9 1 five 3 eight 0 3 two 9 all right okay so permit's do this terminal sum are y'all tired i promise yous are agreement the sum while it's being done three it'southward really quite easy iii 9 one five at this point you lot must be an expert right 8 i think i am 0 3 2 9 okay so let'south first pairing the numbers and i accept a 39 to deal with so vi sixes are 36 and a residue of 3 i bring down the five i double my half-dozen i go 12 and i think 2 is fine hither two twos are iv ii twos are four two ones are two i do the subtraction one seven and i bring downwardly the next two numbers 38 i double my last digit 124 and i think five should exist fine so i put a five here and a v here five fives are xx 5 five fours are 20 into 22 v twos are ten into twelve five ones are 5 and one six i exercise the subtraction i get three here i get one and a nine here i bring down the next two digits which is 0 3 i double this i go l and 12 hither right and a vii should be fine and then seven vii's are 49 7 fives are 35 7 twos are xiv and 3 seventeen seven ones are seven and one viii correct so i do the subtraction i get four and five and eight and 3 is that right something the matter here this is five and this is um no lamentable this should be vii this is a seven i bring down my last two digits for the day and xiv here v and two and let me be satisfied with the three right and then that gives me 3 3's are ix 12 4 3 5's are 15 3 are half dozen and one seven and a three and a zip so this gives me my last square root as vi ii whoops permit me rewrite that vi 2 five 7 3 then that brings me to the end of this sum which had 20 sums in it i hope y'all understood the method do leave a comment in the comment section and visit our channel regularly for homework solutions like this y'all could subscribe to information technology also if yous find it useful cheers so much

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